The number `6n^2+6n` for natural number n is always divisible by 6 only (b) 6 and 12 (c) 12 only...

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"The number `6n^2+6n`for natural number n is always divisible by 6 only (b) 6 and 12 (c) "The number `6n^2+6n`for natural number n is always divisible by 6 only (b) 6 and 12 (c)
Q56- If n is a natural number, then (6n2 + 6n) is always divisible by: Q56- If n is a natural number, then (6n2 + 6n) is always divisible by:
The expression 2^6n - 4^2n , where n is a natural number is always divisible by The expression 2^6n - 4^2n , where n is a natural number is always divisible by
The expression 2^6𝑛− 4^2𝑛, where n is a natural number is always divisible by The expression 2^6𝑛− 4^2𝑛, where n is a natural number is always divisible by
Must Solve Question Series Q16 ( Multiple of 6) Must Solve Question Series Q16 ( Multiple of 6)
"If n even, `(6^n-1)`is divisible by 6 (b) 30 (c) 35 (d) 37" "If n even, `(6^n-1)`is divisible by 6 (b) 30 (c) 35 (d) 37"
( N^3 - N ) - always divisible by 6 - for all natural numbers! ( N^3 - N ) - always divisible by 6 - for all natural numbers!
`7^(6n)-6^(6n),` where n is an integer gt 0, is divisible by 13 (b) 127 (c) 559 (d) All of these `7^(6n)-6^(6n),` where n is an integer gt 0, is divisible by 13 (b) 127 (c) 559 (d) All of these