IIT JEE RELATIONS AND FUNCTIONS Let `f: R ->[0,pi/2)` be defined by `f(x)=tan^(-1)(x^2+x+a)d...

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consider the function f:(0, 2)β†’R defined by f(x) =x/2+2/x & function g(x).. | JEE Mains 2024 #pyqs consider the function f:(0, 2)β†’R defined by f(x) =x/2+2/x & function g(x).. | JEE Mains 2024 #pyqs
Q) Define a relation 𝑅 on the interval [0,πœ‹/2) by π‘₯𝑅𝑦 if and only if sec^2 π‘₯βˆ’tan^2 𝑦=1. Then 𝑅 is : Q) Define a relation 𝑅 on the interval [0,πœ‹/2) by π‘₯𝑅𝑦 if and only if sec^2 π‘₯βˆ’tan^2 𝑦=1. Then 𝑅 is :
Q) Let 𝑓:𝑅→𝑅 be defined by 𝑓(π‘₯)=π‘₯/(1+π‘₯^2 ),π‘₯βˆˆπ‘…. Then the range of 𝑓 is #jee #maths #jee Q) Let 𝑓:𝑅→𝑅 be defined by 𝑓(π‘₯)=π‘₯/(1+π‘₯^2 ),π‘₯βˆˆπ‘…. Then the range of 𝑓 is #jee #maths #jee
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Let `f:R rarr [0, pi//2)` defined by `f(x)=Tan^(-1)(x^(2)+x+a)`, then the |Class 12 MATH | Doubtnut Let `f:R rarr [0, pi//2)` defined by `f(x)=Tan^(-1)(x^(2)+x+a)`, then the |Class 12 MATH | Doubtnut
Q) Let 𝑓:𝑅→𝑅 be defined by 𝑓(π‘₯)=π‘₯/(1+π‘₯^2 ), π‘₯βˆˆπ‘…. Then the range of 𝑓 i #MATHS #jee #jee Q) Let 𝑓:𝑅→𝑅 be defined by 𝑓(π‘₯)=π‘₯/(1+π‘₯^2 ), π‘₯βˆˆπ‘…. Then the range of 𝑓 i #MATHS #jee #jee
Show that function `f: R - gt {x in R : -1 lt x lt 1}` defined by `f(x)=x/(1+|x|), x in R` is on... Show that function `f: R - gt {x in R : -1 lt x lt 1}` defined by `f(x)=x/(1+|x|), x in R` is on...
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