Consider circle (x-alpha)^2+(y-beta)^2=|If circle touches|JEE|Main|session 1|27Feb 2024| Shift 2|NTA

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Consider a circle (x - alpha) ^ 2 + (y - beta) ^ 2 = 50 , where a, beta || Let Consider a circle (x - alpha) ^ 2 + (y - beta) ^ 2 = 50 , where a, beta || Let's IQRA JEE
JEE mains 2024 - Coordinate Geometry: Let the circles C1: (x- alpha)^2 + (y-beta)^2 = r1^2 JEE mains 2024 - Coordinate Geometry: Let the circles C1: (x- alpha)^2 + (y-beta)^2 = r1^2
Let the circles \[{C_1}:{\left( {x - \alpha } \right)^2} + {\left( {y - \beta } \right)^2} = r_12\] Let the circles \[{C_1}:{\left( {x - \alpha } \right)^2} + {\left( {y - \beta } \right)^2} = r_12\]
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Consider a circle C_{1} / (x ^ 2) + y ^ 2 - 4x - 2y = alpha - 5 Let its mirror ima || Let Consider a circle C_{1} / (x ^ 2) + y ^ 2 - 4x - 2y = alpha - 5 Let its mirror ima || Let's IQRA JEE
Consider two circles C1: x2 + y2 = 25 and C2: (x - alpha) * 2 + y * 2 = 16 where || Let Consider two circles C1: x2 + y2 = 25 and C2: (x - alpha) * 2 + y * 2 = 16 where || Let's IQRA JEE