If the function f(x)= {█(2/x {sin(k_1+1)x+sin⁡(k_2-1)x} , x0@ 4 ,

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If the function f(x)= {(2/x {sin(k_1+1)x+sin⁡(k_2-1)x}, x less than 0 , 4 , x=0 2/x〖log〗_ If the function f(x)= {(2/x {sin(k_1+1)x+sin⁡(k_2-1)x}, x less than 0 , 4 , x=0 2/x〖log〗_
Q) If the function𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)+𝑥+sin(𝑘_2−1)𝑥}&,𝑥=0 4,𝑥=0 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥)) Q) If the function𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)+𝑥+sin(𝑘_2−1)𝑥}&,𝑥=0 4,𝑥=0 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))
function 𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)𝑥+sin(𝑘_2−1)𝑥}4 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))is continuous at x=0 function 𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)𝑥+sin(𝑘_2−1)𝑥}4 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))is continuous at x=0
Q) If the function𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)+𝑥+sin(𝑘_2−1)𝑥}&,𝑥=0 4,𝑥=0 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥)) Q) If the function𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)+𝑥+sin(𝑘_2−1)𝑥}&,𝑥=0 4,𝑥=0 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))
Show that the function: f(x)= x^2 *sin(1/x) at x!=0 f(x)= 0 at x=0 is continuous at x=0 ?#shorts Show that the function: f(x)= x^2 *sin(1/x) at x!=0 f(x)= 0 at x=0 is continuous at x=0 ?#shorts
Let f: R to R be a function defined as f(x)={(,(sin (a+1)x + sin2x)/(2x), if x lt 0),(, b, if x=0), Let f: R to R be a function defined as f(x)={(,(sin (a+1)x + sin2x)/(2x), if x lt 0),(, b, if x=0),
function 𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)𝑥+sin(𝑘_2−1)𝑥}4 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))is continuous at x=0 function 𝑓(𝑥)={(2/𝑥 {sin(𝑘_1+1)𝑥+sin(𝑘_2−1)𝑥}4 2/𝑥 log_𝑒 ((2+𝑘_1 𝑥)/(2+𝑘_2 𝑥))is continuous at x=0
Checking the Continuity of a Function #jeedailyconcepts #limitsandcontinuity Checking the Continuity of a Function #jeedailyconcepts #limitsandcontinuity