Prove tan(pi/4 - x)/tan(pi/4 + x) = ((1 – tan x)/ (1 + tan x))^2

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Prove tan(pi/4 + x)/tan(pi/4 - x) = ((1 + tan x)/ (1 - tan x))^2 Prove tan(pi/4 + x)/tan(pi/4 - x) = ((1 + tan x)/ (1 - tan x))^2
Prove that tan⁡(π/4+x)/tan⁡(π/4-x) =((1+tan⁡x)/(1-tan⁡x ))^2 Prove that tan⁡(π/4+x)/tan⁡(π/4-x) =((1+tan⁡x)/(1-tan⁡x ))^2
'tan (pi/4+x)/tan(pi/4-x) = [(1 + tanx)(1- tanx)] ^2' || tan(π/4+x)/tan(π/4-x)=(1+tanx/1-tanx)^2
`(tan.((pi)/(4)+x))/(tan.((pi)/(4)-x)) =((1+tan x)/(1-tan x))^(2)` `(tan.((pi)/(4)+x))/(tan.((pi)/(4)-x)) =((1+tan x)/(1-tan x))^(2)`
Prove that :- tan (π/4 - x) = (1 - tanx)/(1 + tanx) Prove that :- tan (π/4 - x) = (1 - tanx)/(1 + tanx)
Prove that tan(π/4+x)/tan(π/4-x)=(1+tan x/1-tan x)^2 Prove that tan(π/4+x)/tan(π/4-x)=(1+tan x/1-tan x)^2
[IIT 1994] Prove that sec2x - tan2x = tan (PI/4 - x) when x lies between 0 and PI/4. [IIT 1994] Prove that sec2x - tan2x = tan (PI/4 - x) when x lies between 0 and PI/4.
Prove that :- tan(π/4 + x) = (1 + tanx)/(1 + tanx) Prove that :- tan(π/4 + x) = (1 + tanx)/(1 + tanx)