If y=(x^2-1)^n, show that (x^2-1)yn+1+2xyn+1-n(n+1)yn=0.Hence if P(x=1/2^n.n!d^n/dx^n{(x^2-1)^n}),sh

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If y=(x^2-1)^n ,prove that (x^2-1)yn+2 +2xyn+1 - n(n+1)yn =0 Hence if Pn = d^n/dx^n {(1-x^2)dPn/dx..

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