If 5f(x) + 4f(1/x) = x²-2 and y=9x² then y is strictly increasing in... | jee mains 2024 maths

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Q) If 5𝑓(x)+4𝑓(1/x)=x^2−2, y=9x^2 𝑓(𝑥), then 𝑦 is strictly increasing in #applicationofderivatives Q) If 5𝑓(x)+4𝑓(1/x)=x^2−2, y=9x^2 𝑓(𝑥), then 𝑦 is strictly increasing in #applicationofderivatives
If 5 f(x)+4f(1/x)=x² -2, ∀x ≠ 0 and y=9x² f(x),then y is strictly increasing in: If 5 f(x)+4f(1/x)=x² -2, ∀x ≠ 0 and y=9x² f(x),then y is strictly increasing in:
If 5f(x) + 4f(1/x) = x² - 2 x ne0 and y = 9x². f(x) then y is strictly increasing in If 5f(x) + 4f(1/x) = x² - 2 x ne0 and y = 9x². f(x) then y is strictly increasing in
If 5f(x) + 4f(𝟏/𝒙) = 𝒙^𝟐 – 2, ∀x ≠ 0 and y = 9𝒙^𝟐f(x), then y is strictly increasing in(1) (𝟎,𝟏/√𝟓) If 5f(x) + 4f(𝟏/𝒙) = 𝒙^𝟐 – 2, ∀x ≠ 0 and y = 9𝒙^𝟐f(x), then y is strictly increasing in(1) (𝟎,𝟏/√𝟓)
If f(x)+4f(1/x)=x^2-2, x is not equal to 0 and y=9x^2f(x), then y is strictly increasing in: If f(x)+4f(1/x)=x^2-2, x is not equal to 0 and y=9x^2f(x), then y is strictly increasing in:
Q) Let 5𝑓(𝑥)+4𝑓(1/𝑥)=1/𝑥+3, Then 18∫_1^2 𝑓(𝑥)𝑑𝑥 is #jee #maths #jeemains #jee2025 #maths Q) Let 5𝑓(𝑥)+4𝑓(1/𝑥)=1/𝑥+3, Then 18∫_1^2 𝑓(𝑥)𝑑𝑥 is #jee #maths #jeemains #jee2025 #maths
Q) Let 5𝑓(𝑥)+4𝑓(1/𝑥)=1/𝑥+3, Then 18∫_1^2 𝑓(𝑥)𝑑𝑥 is #jee #maths #jeemains #jee2025 #maths Q) Let 5𝑓(𝑥)+4𝑓(1/𝑥)=1/𝑥+3, Then 18∫_1^2 𝑓(𝑥)𝑑𝑥 is #jee #maths #jeemains #jee2025 #maths
5 f(x) + 4 f(1/x) = x^2 -4 and y=9f(x).x^2 if y is strictly increasing function,find interval of x 5 f(x) + 4 f(1/x) = x^2 -4 and y=9f(x).x^2 if y is strictly increasing function,find interval of x