🌸Limits lim to 1 (x ^ 2 - ax + b)/(x - 1) = 5, find a+b, Important Maths Problems for IIT JEE

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lim x→1 (x² -ax+b)/(x-1) = 5. a = ? b = ? JEE-Main India, 10 Apr 2019, Evening Shift, Question 60. lim x→1 (x² -ax+b)/(x-1) = 5. a = ? b = ? JEE-Main India, 10 Apr 2019, Evening Shift, Question 60.
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If lim┬(x→1)⁡〖(x^2-ax+b)/(x-1)=5〗, then a+b is equal to #limitandcontinuity @EasyMath4Jeee#iitjee If lim┬(x→1)⁡〖(x^2-ax+b)/(x-1)=5〗, then a+b is equal to #limitandcontinuity @EasyMath4Jeee#iitjee
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If `underset(x to 1)lim (x^(2) - ax + b)/(x-1)=5," then " a + b ` is equal to If `underset(x to 1)lim (x^(2) - ax + b)/(x-1)=5," then " a + b ` is equal to
17. IIT-JEE Trick #maths #iitjee #iit #mathematics #india #jee #math #students #study #student #kota 17. IIT-JEE Trick #maths #iitjee #iit #mathematics #india #jee #math #students #study #student #kota