1 – Sec 8 alpha / 1 – Sec 4 alpha = tan 8 alpha/ tan 2 alpha @EAG

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Prove that (1–sec 8 alpha ) / (1–sec 4 alpha) = tan 8 alpha/tan 2 alpha Prove that (1–sec 8 alpha ) / (1–sec 4 alpha) = tan 8 alpha/tan 2 alpha
`tanalpha+2tan2alpha+4tan4alpha+8cot8alpha=cotalpha` `tanalpha+2tan2alpha+4tan4alpha+8cot8alpha=cotalpha`
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(sec(8theta) - 1)/(sec(4theta) - 1) = (tan 8theta)/(tan 2theta) (sec(8theta) - 1)/(sec(4theta) - 1) = (tan 8theta)/(tan 2theta)
`tan alpha + 2tan 2alpha + 4tan4alpha + 8cot8alpha` is equal to: `tan alpha + 2tan 2alpha + 4tan4alpha + 8cot8alpha` is equal to:
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