In AP a= 3, n= 8, sum of term is 192 find common difference d | Its Study time| cl-10 Ex-5.3-3(ix)

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Ex 5.3, 3 (ix) - In an AP (ix) Given a = 3, n = 8, S = 192, find d - Teachoo Ex 5.3, 3 (ix) - In an AP (ix) Given a = 3, n = 8, S = 192, find d - Teachoo
Ex:5.3 Q-3. In an AP: (ix) given a = 3, n = 8, S = 192, find d Ex:5.3 Q-3. In an AP: (ix) given a = 3, n = 8, S = 192, find d
(ix) Given a = 3, n = 8, S = 192 , find d.#shorts #arithmeticprogression #cbseclass10 #sslc maths (ix) Given a = 3, n = 8, S = 192 , find d.#shorts #arithmeticprogression #cbseclass10 #sslc maths
Arithmetic Progressions Exercise-5.3 Solution (Part-5) #learnwithakku #learn #ncert #maths #viral Arithmetic Progressions Exercise-5.3 Solution (Part-5) #learnwithakku #learn #ncert #maths #viral
Arithmetic Progressions Exercise-5.3 Solution (Part-11) #learnwithakku #learn #ncert #maths #viral Arithmetic Progressions Exercise-5.3 Solution (Part-11) #learnwithakku #learn #ncert #maths #viral
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|(ix) GivenĀ a=3,n=8,S=192, findĀ d.| #ap #shortsfeed #youtubeshorts #mathsshorts #shortsfeed2023 |(ix) GivenĀ a=3,n=8,S=192, findĀ d.| #ap #shortsfeed #youtubeshorts #mathsshorts #shortsfeed2023
In an AP | (ix) given a = 3, n = 8, S = 192, find d | Class 10th Maths Chapter 5 Exercise 5.3 NCERT In an AP | (ix) given a = 3, n = 8, S = 192, find d | Class 10th Maths Chapter 5 Exercise 5.3 NCERT