Cot of summation from n=1 to 19 of cot inverse of (1+summation from p=1 to 19 of 2p)

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The value of cot(Sigma n=1 to 19 cot^-1(1+Sigma p=1 to n 2p)) is inverse trigonometric#iitjee mains, The value of cot(Sigma n=1 to 19 cot^-1(1+Sigma p=1 to n 2p)) is inverse trigonometric#iitjee mains,
The value of cot⁡(∑_(n=1)^19▒〖〖cot〗^(-1) (1+∑_(p=1)^n▒2p) 〗) is a) 23/22 b) 22/23 c) 19/21 The value of cot⁡(∑_(n=1)^19▒〖〖cot〗^(-1) (1+∑_(p=1)^n▒2p) 〗) is a) 23/22 b) 22/23 c) 19/21
The value of cotsum_(n=1)^(19)cot^(-1)(1+sum_(p=1)^(n)2p) is equal to (a) (21)/(19)(b) (19)/(21)... The value of cotsum_(n=1)^(19)cot^(-1)(1+sum_(p=1)^(n)2p) is equal to (a) (21)/(19)(b) (19)/(21)...
problems on inverse trigonometric functions, The value ofcot⁡(∑_(n=1)^19▒〖cot〗^(-1)⁡(1+∑_(p=1)^n▒2p) problems on inverse trigonometric functions, The value ofcot⁡(∑_(n=1)^19▒〖cot〗^(-1)⁡(1+∑_(p=1)^n▒2p)
The value of cot⁡(∑_(n=1)^19▒cot^(-1)⁡(1+∑_(p=1)^n▒2p) ) is The value of cot⁡(∑_(n=1)^19▒cot^(-1)⁡(1+∑_(p=1)^n▒2p) ) is
Find the value of cot [ sigma n=1 to 50 tan inverse of (1/(1+n+n^2)] Find the value of cot [ sigma n=1 to 50 tan inverse of (1/(1+n+n^2)]
The value of cot(∑_(n=1)^23▒〖〖cot〗^(-1) (1+∑_(k=1)^n▒2k) 〗)is The value of cot(∑_(n=1)^23▒〖〖cot〗^(-1) (1+∑_(k=1)^n▒2k) 〗)is
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