If f(x) satisfies the functional equation f(x) + 6 f(1/x) = 35/3x - 7/2 , x ∈ R −{0} | JEE MAIN 2025

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Q) Let 𝑓:𝑅={0}→ℝ be a function such that 𝑓(𝑥)=6𝑓(1/𝑥)=35/3𝑥−5/2, If the lim(𝑥→0) (1/𝛼𝑥+𝑓(𝑥))=𝛽;

Let f : R-{0} →R be function such that f(x) – 6f(1/x) = (35/3x) - (5/2).If lim┬(x→0)⁡((1/αx) + f(x))

Let f : R-{0} →R be a function such that f(x) – 6f(1/x) = 35/3x- 5/2 . If the lim┬(x→0)⁡〖(1/αx+f(

Q) Let f:ℝ−{0}→ℝ be a function 𝑓(𝑥)−6𝑓(1/𝑥)=35/3𝑥−5/2 If the lim(𝑥→0) (1/𝛼𝑥+𝑓(𝑥))=𝛽; 𝛼,𝛽∈ℝ,then 𝛼+2𝛽

M16_A real valued function f(x) satisfies the functional equation f(x-y)=f(x)f(y)-f(a-x)f(a+y) where

Let f:R-{0} be a function such that f(x)-6f(1/x)=35/3x-5/2 |11|JEE Main|2025|Entrance|24th Jan|IIT

Let f:R-{0} → R be a function such that f(x) − 6f (1/x) =35/3x −5/2. If the limx→0 (1/αx + f(x))= β

Let 𝑓:𝑅={0}→ℝ be a function such that 𝑓(𝑥)=6𝑓(1/𝑥)=35/3𝑥−5/2, If the lim(𝑥→0) (1/𝛼𝑥+𝑓(𝑥))=𝛽;