if G be finite group and a be any element of G s.t. o(a)=n them a^m=e iff n|m

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Let G be a group, a ɛ G and O(a)=n. Then a^m=e iff n|m. Let G be a group, a ɛ G and O(a)=n. Then a^m=e iff n|m.
If the element If the element 'a' of a group G is of order n, then a^m =e iff n is a divisor of m || Group Theory.
(Abstract Algebra 1) Basic Group Proof 3 (Abstract Algebra 1) Basic Group Proof 3
#theorem- If G is a finite group,then O(G) =∑O(G)/O(Na) where this sum is taken over #ConjugateClass #theorem- If G is a finite group,then O(G) =∑O(G)/O(Na) where this sum is taken over #ConjugateClass
theorem group theory :-If order of element a of group G is n then, a^m=e, iff m is multiple of n theorem group theory :-If order of element a of group G is n then, a^m=e, iff m is multiple of n
2.1.26 :: Herstein Chapter 2, Section 1, Problem 27 Herstein Abstract Algebra 2.1.26 :: Herstein Chapter 2, Section 1, Problem 27 Herstein Abstract Algebra
If the element If the element 'a' of a group G is order n, then a^m= e iff n is a divisor of m
a^(m) is a generator of group G of order n iff GCD(m,n)=1 a^(m) is a generator of group G of order n iff GCD(m,n)=1