Q Prove that 2a^2+2b^2+2c^2-2ab-2bc-2ca=(a-b)^2+(b-c)^2+(c-a)^2

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"Prove that: `2a^2+2b^2+2c^2-2a b-2b c-2c a=(a-b)^2+(b-c)^2+(c-a)^2`" "Prove that: `2a^2+2b^2+2c^2-2a b-2b c-2c a=(a-b)^2+(b-c)^2+(c-a)^2`"
proof// (a-b)^2= a^2-2ab+b^2 // proof// (a-b)^2= a^2-2ab+b^2 //
(a+b) ² = a² + 2ab + b² Maths important formula (a+b) ² = a² + 2ab + b² Maths important formula
Prove that: `2a^2+2b^2-2a b-2b c-2c a=[(a-b)^2+(b-c)^2+(c-a)^2]` Prove that: `2a^2+2b^2-2a b-2b c-2c a=[(a-b)^2+(b-c)^2+(c-a)^2]`
#Formula (a+b)²=a²+b²+2ab #solution #Formula (a+b)²=a²+b²+2ab #solution
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Prove that: 2a²+2b²+2c²-2ab-2bc-2ca = [ (a-b)²+(b-c)²+(c-a)² ] Prove that: 2a²+2b²+2c²-2ab-2bc-2ca = [ (a-b)²+(b-c)²+(c-a)² ]
How To Calculate (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca?? How To Calculate (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca??