Let f:R→R defined f (x) = ae²x+bex+ cx.if f(0)=1,f'(loge 2) =21 and ∫ (f(x)- cx) dx= 39/2, then the

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Let f:R→R be defined as f(x)=ae^2x+be^x+cx. If f(0)=-1,f Let f:R→R be defined as f(x)=ae^2x+be^x+cx. If f(0)=-1,f'(loge⁡2)=21 ; ∫0^(loge⁡4) (f(x)-cx)dx=39/2
If f(x)= 3x-2 if 0 less than x ≤1 and 2x²+ax if 1less than x less than 2 is continyous for x ⋳(0,2) If f(x)= 3x-2 if 0 less than x ≤1 and 2x²+ax if 1less than x less than 2 is continyous for x ⋳(0,2)
If f(x)=a+bx+cx² then show that ∫f(x)dx with limits 0 to 1 = 1/6[f(0)+4f(1/2)+f(1)] | If f(x)=a+bx+cx² then show that ∫f(x)dx with limits 0 to 1 = 1/6[f(0)+4f(1/2)+f(1)] |
Let f:R-R be defined asf(x)=ae2x+bex+cx.If f(0)=-1,f’(log2)=21,integration from0to log4 (f(x) -cx)dx Let f:R-R be defined asf(x)=ae2x+bex+cx.If f(0)=-1,f’(log2)=21,integration from0to log4 (f(x) -cx)dx
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if f(x)=a+bx+cx² show that integral f(x) from 0 to 1=1/6[f(0)+4f(½)+f(1)] if f(x)=a+bx+cx² show that integral f(x) from 0 to 1=1/6[f(0)+4f(½)+f(1)]
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