x g of metal (equivalent wt=12) was completely dissolved in 100 cc of N/2 HCl. The volume was then …

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Xg of a metal (eqv. wt=12) was completely dissolved in 100 ml of N/2 HCL. The volume is then made up Xg of a metal (eqv. wt=12) was completely dissolved in 100 ml of N/2 HCL. The volume is then made up
Xg of a metal (equ. wt=12) was completely dissolved in 100cc of N/2 HCl solution . It is found that Xg of a metal (equ. wt=12) was completely dissolved in 100cc of N/2 HCl solution . It is found that
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0.18g of metal was completely dissolved in 100mL of HCI. The volume was then made up to 500mL. 0.18g of metal was completely dissolved in 100mL of HCI. The volume was then made up to 500mL.
4g of a divalent metal was dissolved in 100cc of 2M H2sou4(f=1.01). The excess and required 30cc of 4g of a divalent metal was dissolved in 100cc of 2M H2sou4(f=1.01). The excess and required 30cc of
0.18g of a divalent metal was completely dissolved in 250cc of acid solution containing 4.9g H2so4/L 0.18g of a divalent metal was completely dissolved in 250cc of acid solution containing 4.9g H2so4/L