06 G be a group of identity element e and a,b∈G be such that a^5=e & aba^(-1)=b^2 then O(b) is

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#04 trick of abstarct algebra | If in a group G , a^5=e ,aba^-1 =b^2 , then order of b is #04 trick of abstarct algebra | If in a group G , a^5=e ,aba^-1 =b^2 , then order of b is
IF , IN A GROUP G , X^2 = e ( IDENTITY ) FOR ALL X IN G [ THAT IS , IF EVERY ELEMENT OF G ( EXCEPT IF , IN A GROUP G , X^2 = e ( IDENTITY ) FOR ALL X IN G [ THAT IS , IF EVERY ELEMENT OF G ( EXCEPT
Identity element e is unique# Inverse element is unique# (aob)^-1 = b^-1oa^-1. Identity element e is unique# Inverse element is unique# (aob)^-1 = b^-1oa^-1.
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If the binary operation * on the set Z is defined by a*b=a+b-5, then find the identity element with If the binary operation * on the set Z is defined by a*b=a+b-5, then find the identity element with
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finding the identity element and the inverse of 8 for a binary operation finding the identity element and the inverse of 8 for a binary operation
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