If `a b+b c+c a=0` , then what is the value of `(1/(a^2-b c)+1/(b^2-c a)+1/(c^2-a b))` ? (a) 0 (...

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Q344 | If ab+bc+ca=0, then what is the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab)? | Algebra Q344 | If ab+bc+ca=0, then what is the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab)? | Algebra
Polynomial | If ab+bc+ca=0 | Find the value of 1/a²-bc + 1/b²-ca +1/c²-ab | Can you solve this? Polynomial | If ab+bc+ca=0 | Find the value of 1/a²-bc + 1/b²-ca +1/c²-ab | Can you solve this?
"If `a b+b c+c a=0`, then what is the value of `(1/(a^2-b c)+1/(b^2-c a)+1/(c^2-a b))` "If `a b+b c+c a=0`, then what is the value of `(1/(a^2-b c)+1/(b^2-c a)+1/(c^2-a b))`
if ab+bc+ca=0 then find the value of 1/a^2-bc+1/b^2-ca+1/c^2-ab | prove 1/a^2-bc+1/b^2-ca+1/c^2-ab=0 if ab+bc+ca=0 then find the value of 1/a^2-bc+1/b^2-ca+1/c^2-ab | prove 1/a^2-bc+1/b^2-ca+1/c^2-ab=0
If ab + bc + ca = 0 then the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab) If ab + bc + ca = 0 then the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab)
If ab + bc + ca = 0 then find the value of- 1/(a ^ 2 - bc) + 1/(b ^ 2 - ca) + 1/(c ^ 2 - ab) ´| If ab + bc + ca = 0 then find the value of- 1/(a ^ 2 - bc) + 1/(b ^ 2 - ca) + 1/(c ^ 2 - ab) ´|
A Nice Algebra Question | ab + bc + ca = 0 , 1/a^2-bc + 1/b^2-ca + 1/c^2-ab = ? A Nice Algebra Question | ab + bc + ca = 0 , 1/a^2-bc + 1/b^2-ca + 1/c^2-ab = ?
If a+b+c=0, then prove that a^2/(2a²+bc) + b²/(2b²+ac) + c²/(2c²+ab) =1. If a+b+c=0, then prove that a^2/(2a²+bc) + b²/(2b²+ac) + c²/(2c²+ab) =1.