The area bounded by the circle x^2+y^2=4, line x=√3 y and x-axis lying in the first quadrant, is

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find the area of the region enclosed by x-axis line x=√3y and the circle x²+y²=4 find the area of the region enclosed by x-axis line x=√3y and the circle x²+y²=4
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Given the area in the first quadrant bounded by the curve x^2 = 8y, the line x = 4 and the x– axis.… Given the area in the first quadrant bounded by the curve x^2 = 8y, the line x = 4 and the x– axis.…
Area bounded by y²=x, x=1, x=4 and X axis in first quadrant #shorts #calculus #gujcet #integrals Area bounded by y²=x, x=1, x=4 and X axis in first quadrant #shorts #calculus #gujcet #integrals