In figure, if ∠1 = ∠ 2 and ∆ ≅ ∆ NSQ MTR, then prove that ∆ PTS ~ ∆ PRQ

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2. In Fig, if angle 1 = angle 2 and triangle NSQ = triangle MTR, then prove that PTS ~ PRQ. 2. In Fig, if angle 1 = angle 2 and triangle NSQ = triangle MTR, then prove that PTS ~ PRQ.
in the given figure angle 1= angle 2 and ∆NSQ CONGRUENT ∆MTR. Then prove that ∆PTS ~ ∆PRQ. in the given figure angle 1= angle 2 and ∆NSQ CONGRUENT ∆MTR. Then prove that ∆PTS ~ ∆PRQ.
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In given figure ∠1 = ∠2 and ΔNSQ ≅ ΔMTR , then prove that ΔPTS ~ ΔPRQ | Class 10 Maths Triangles In given figure ∠1 = ∠2 and ΔNSQ ≅ ΔMTR , then prove that ΔPTS ~ ΔPRQ | Class 10 Maths Triangles
In figure, if `angle1=angle2` and `DeltaNSQ=DeltaMTR`, then prove that `DeltaPTS~DeltaPRQ`. In figure, if `angle1=angle2` and `DeltaNSQ=DeltaMTR`, then prove that `DeltaPTS~DeltaPRQ`.
In figure angle1=angle2 and 📐NSQ congruent to 📐MTR, then prove that 📐PTS~ 📐 PRQ. In figure angle1=angle2 and 📐NSQ congruent to 📐MTR, then prove that 📐PTS~ 📐 PRQ.