In a ∆ABC, the internal bisector of angle B and angle C meet at O. if angle BAC=72°, then the value

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In a △ABC, the internal bisectors of ∠B and ∠C meet at O. if angle ∠BAC = 72 deg , then the In a △ABC, the internal bisectors of ∠B and ∠C meet at O. if angle ∠BAC = 72 deg , then the
∠B=2∠C. BC such that AD bisects ∠BAC and AB=CD. BE is the bisector of ∠B. ∠BAC = 72° ∠B=2∠C. BC such that AD bisects ∠BAC and AB=CD. BE is the bisector of ∠B. ∠BAC = 72°
In a ∆ABC,the bisectors of B and C intersect each other point o.prove BOC =90° +1/2A In a ∆ABC,the bisectors of B and C intersect each other point o.prove BOC =90° +1/2A
In Δ ABC, the internal bisectors of ∠B and ∠C meet at point O. If∠A = 80°, then ∠BOC is equal to : In Δ ABC, the internal bisectors of ∠B and ∠C meet at point O. If∠A = 80°, then ∠BOC is equal to :
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30. The internal bisectors of ∠B and ∠C of ⧍ABC meet at D. If ∠A = 75°, the ∠BDC is : 30. The internal bisectors of ∠B and ∠C of ⧍ABC meet at D. If ∠A = 75°, the ∠BDC is :
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