Show that tan(A+B)/2=CotC/2 in a ∆ABC@Mareedulakshmi

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IN TRIANGLE ABC, SHOW THAT tan( C+A ) / 2 = cot B/2 IN TRIANGLE ABC, SHOW THAT tan( C+A ) / 2 = cot B/2
Show that in a triangle ABC, cot(A/2) + cot(B/2) + cot(C/2) = cot(A/2)*cot(B/2)*cot(C/2) Show that in a triangle ABC, cot(A/2) + cot(B/2) + cot(C/2) = cot(A/2)*cot(B/2)*cot(C/2)
In a `DeltaABC`, prove that `tan((A+B)/2)=cot(c/2)` In a `DeltaABC`, prove that `tan((A+B)/2)=cot(c/2)`
• Prove That - tan(B+C/2) = cot(A/2) If A, B, C are the angles of ∆ABC | Trigonometry | ShikshaShila • Prove That - tan(B+C/2) = cot(A/2) If A, B, C are the angles of ∆ABC | Trigonometry | ShikshaShila
In any `DeltaABC`, prove that:` (a+b-c)/(a+b+c) = tan (A/2) tan (B/2)` In any `DeltaABC`, prove that:` (a+b-c)/(a+b+c) = tan (A/2) tan (B/2)`
In a triangle ABC, tan A/2 = 5/6, tan B/2 = 20/37, then show that tan C/2 is equal to 2/5 In a triangle ABC, tan A/2 = 5/6, tan B/2 = 20/37, then show that tan C/2 is equal to 2/5
Show that in any triangle `ABC, (a+b+c) (tan (A/2) + tan (B/2)) = 2c cot (C/2)` Show that in any triangle `ABC, (a+b+c) (tan (A/2) + tan (B/2)) = 2c cot (C/2)`
Solve tan²A + cot²A Solve tan²A + cot²A