If `log ((a-b)/2)=1/2(loga+logb),` show that `a^2+b^2=6ab`

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If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b` If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b`
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If log (a+b/2) = log + log b/2, find /b + b/a If log (a+b/2) = log + log b/2, find /b + b/a
If log (a-b)/(2) = (1)/(2) (log a + log b), show that : a^(2) + b^(2) = 6ab. | 9 | LOGARITHMS ... If log (a-b)/(2) = (1)/(2) (log a + log b), show that : a^(2) + b^(2) = 6ab. | 9 | LOGARITHMS ...
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