The sum of n, 2n, 3n terms of an A.P. are S1, S2 and S3 respectively. Prove that S3=3(S2-S1).

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If the sum of first n, 2n and 3n terms of an AP be S1, S2 and S3 respectively prove that S3=3(S2-S1) If the sum of first n, 2n and 3n terms of an AP be S1, S2 and S3 respectively prove that S3=3(S2-S1)
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Let the sum of n,2n,3n terms of an A.P. be S1,S2 and S3 respectively. Show that S3=3(s2-s1) Let the sum of n,2n,3n terms of an A.P. be S1,S2 and S3 respectively. Show that S3=3(s2-s1)
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The sum of n,2n,3n terms of an AP be S1,S2,S3 respectively. Show that S3= 3(S2-S1) The sum of n,2n,3n terms of an AP be S1,S2,S3 respectively. Show that S3= 3(S2-S1)
Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3 , respectively, show that S3 = 3(S2 - S1) Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3 , respectively, show that S3 = 3(S2 - S1)
Let the sum of n, 2n, 3n terms of an A.P. be `S_1,S_2`and `S_3`, respectively, show that Let the sum of n, 2n, 3n terms of an A.P. be `S_1,S_2`and `S_3`, respectively, show that