If `a_n=sum(1/C(n,r)` from r=0 to n, then `sum(r/C(n,r))` from r=0 to n is

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If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n` If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n`
Prove that Sum((-1)^n * (n choose r)) = 0 Prove that Sum((-1)^n * (n choose r)) = 0
Sn=summation r=0 to n 1/ncr tn=summation r=0 to n r/ncr then tn/sn=? Sn=summation r=0 to n 1/ncr tn=summation r=0 to n r/ncr then tn/sn=?
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Let f(x)=lim n→∞ sum r=0 to n(tan(x/2^(r+1))+tan³(x/2^(r+1))/1-tan²(x/2^(r+1))) Then limx→0(e^x-e^f Let f(x)=lim n→∞ sum r=0 to n(tan(x/2^(r+1))+tan³(x/2^(r+1))/1-tan²(x/2^(r+1))) Then limx→0(e^x-e^f
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