Prove that log(75/16)-2log(5/9)+log(32/243)=log2 | logarithms | SSC | CLASS 10 MATHEMATICS

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Prove that log 75/16 - 2log5/9 + log 32/243 = log2 | Logarithmic Question Prove that log 75/16 - 2log5/9 + log 32/243 = log2 | Logarithmic Question
log 75/16 - 2 log 5/9 + log 32/243....reduce the following....Laws of logarithm #mirztuition log 75/16 - 2 log 5/9 + log 32/243....reduce the following....Laws of logarithm #mirztuition
Express \(log(75/16) - 2log(5/9) + log(32/243)\) in terms of log 2 and log 3.... Express \(log(75/16) - 2log(5/9) + log(32/243)\) in terms of log 2 and log 3....
Simplify : log(75)/( 16) - 2 log ( 5)/(9)+log( 32)/(243) | 9 | CHAPTERWISE REVISION (STAGE 1) ... Simplify : log(75)/( 16) - 2 log ( 5)/(9)+log( 32)/(243) | 9 | CHAPTERWISE REVISION (STAGE 1) ...
Prove that \( \log \frac{75}{16}-2 \log \frac{5}{9}+\log \frac{32}{243}=\log 2 \) Prove that \( \log \frac{75}{16}-2 \log \frac{5}{9}+\log \frac{32}{243}=\log 2 \)
11th Std Maths Example 2.36 Prove log 75/16 - 2 log 5/9 + log 32/243 = log 2 11th Std Maths Example 2.36 Prove log 75/16 - 2 log 5/9 + log 32/243 = log 2
Simplify `: log\ 75/16 - 2 log\ 5/9 + log\ 32/243` Simplify `: log\ 75/16 - 2 log\ 5/9 + log\ 32/243`
11th maths Basic Algebra chapter 2 example 2.36 tn syllabus hiba maths 11th maths Basic Algebra chapter 2 example 2.36 tn syllabus hiba maths