If sin theta + cos theta = x, prove that sin^6 theta + cos^6 theta = (4-3(x^2-1)^2)/4 / Trigonometry

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RD Sharma Class 10 EX 11.1 Q 49: If sin theta+cos theta=x prove sin^6 theta+cos^6 theta=4-3(x^2-1)^2 RD Sharma Class 10 EX 11.1 Q 49: If sin theta+cos theta=x prove sin^6 theta+cos^6 theta=4-3(x^2-1)^2
If `sintheta+ costheta=x` then prove that `sin^6theta+ cos^6theta=(4-3*(x^2-1)^2)/4` If `sintheta+ costheta=x` then prove that `sin^6theta+ cos^6theta=(4-3*(x^2-1)^2)/4`
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If `sintheta+costheta=x ,` Prove that : `sin^6theta+cos^6theta=(4-3(x^2-1)^2)/4` If `sintheta+costheta=x ,` Prove that : `sin^6theta+cos^6theta=(4-3(x^2-1)^2)/4`