Find the value of k for which f(x)= 1-cos4x/8x^2, when x≠0 & k, when x=0, is continuous at x=0.

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Find k for which f(x)= (1-cos4x)/8x^2 if x≠0 and k if x=0 is continuous at 0. Find k for which f(x)= (1-cos4x)/8x^2 if x≠0 and k if x=0 is continuous at 0.
Find k for f(x) =(1-cos4x)/8x^2 𝑖𝑓 𝑥≠0, 𝑘 𝑖𝑓 𝑥=0 is continuous at x=0| SECTION A| NCERT| Class 12 Find k for f(x) =(1-cos4x)/8x^2 𝑖𝑓 𝑥≠0, 𝑘 𝑖𝑓 𝑥=0 is continuous at x=0| SECTION A| NCERT| Class 12
The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is
Function `f(x) = (1-cos 4x)//(8x^(2)), " where " x != 0 ` , and f(x) = k, where x = 0 , is a c Function `f(x) = (1-cos 4x)//(8x^(2)), " where " x != 0 ` , and f(x) = k, where x = 0 , is a c
The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is #maths The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is #maths
The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is The value of k for which the function f(x)={((1−cos4𝑥)/(8𝑥^2 ) , if 𝑥≠0 𝑘, if 𝑥=0 is
If the function `f(x) {((1 - cos 4x)/(8x^(2))",",x !=0),(" k,",x = 0):}`is continuous at If the function `f(x) {((1 - cos 4x)/(8x^(2))",",x !=0),(" k,",x = 0):}`is continuous at
For what value of k, the function given below is continuous at x=0 f(x)=(√(4+x) - 2)/x , x≠0 k, x=0 For what value of k, the function given below is continuous at x=0 f(x)=(√(4+x) - 2)/x , x≠0 k, x=0