If X={4^n-3n-1: n€N} and Y={9(n-1):n€N} then XUY is equal to

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If X={4^(n)-3n-1:n in N} and {9(n-1):n in N}, the prove that X sub Y. | 11 | SETS | MATHS | NAGE... If X={4^(n)-3n-1:n in N} and {9(n-1):n in N}, the prove that X sub Y. | 11 | SETS | MATHS | NAGE...
If `X={4^n-3n-1: n epsilonN}&Y={9(n-1):n epsilonN}`,then precisely If `X={4^n-3n-1: n epsilonN}&Y={9(n-1):n epsilonN}`,then precisely
if x={4^n -3n-1:neN}, and y={9(n-1):nEN} ,where Nis the set of natural number , then XUY=?(jee 2015 if x={4^n -3n-1:neN}, and y={9(n-1):nEN} ,where Nis the set of natural number , then XUY=?(jee 2015
If `A={4^(n)-3n-1:n in N) and B={9(n-1):n in N}` then If `A={4^(n)-3n-1:n in N) and B={9(n-1):n in N}` then
Use MI to prove 1/(1×4 )+1/(4×7)+1/(7×10)+........=n/(3n+1) for all n€ N Use MI to prove 1/(1×4 )+1/(4×7)+1/(7×10)+........=n/(3n+1) for all n€ N
If X={4n−3n−1:n∈N} and Y={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Y is If X={4n−3n−1:n∈N} and Y={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Y is
Why does sum of all Natural Numbers = -1/12? | Manim | Why does sum of all Natural Numbers = -1/12? | Manim |
If `X={4^(n)-3n-1,ninN}andY={9(n-1):ninN}," then "XcapY=` If `X={4^(n)-3n-1,ninN}andY={9(n-1):ninN}," then "XcapY=`