If the system of equations 2x+3y=5, 4x+ky=10 has infinitely many solutions, then k=|MCQ RD Class 10

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If the system of equations `2x+3y=5,\ \ \ \ 4x+k y=10` has infinitely many solutions, then If the system of equations `2x+3y=5,\ \ \ \ 4x+k y=10` has infinitely many solutions, then
If the system of equations 2x+3y=5, 4x+ky=10 has infinitely many solutions, then k=(a) 1(b) 1/2(c) If the system of equations 2x+3y=5, 4x+ky=10 has infinitely many solutions, then k=(a) 1(b) 1/2(c)
The value of `k` for which the system of equations `2x+3y=5,\ \ \ \ 4x+k y=10` has infinite The value of `k` for which the system of equations `2x+3y=5,\ \ \ \ 4x+k y=10` has infinite
Equations 2x+3y=5 and 4x+ky=10 has infinitely many solutions, then value of k is Equations 2x+3y=5 and 4x+ky=10 has infinitely many solutions, then value of k is
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Find value of k for which equation 2x+3y=5 and 4x+ky=10 has infinitely many solution| class 10 Find value of k for which equation 2x+3y=5 and 4x+ky=10 has infinitely many solution| class 10
"The pair of linear equations 2x+3y=5 and 4x+ky=10 has infinite | Class 10 Maths | Doubtnut "The pair of linear equations 2x+3y=5 and 4x+ky=10 has infinite | Class 10 Maths | Doubtnut
One Solution, No Solution, or Infinitely Many Solutions - Consistent & Inconsistent Systems One Solution, No Solution, or Infinitely Many Solutions - Consistent & Inconsistent Systems