(cosecθ−cotθ)2 = (1+cosθ) / (1−cosθ) | cosec theta - cot theta whole square​

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Prove that : (Cosecθ - cotθ)^2 = 1-cosθ/1+cosθ ...|| Class 10 || NCERT Maths & rd question || Prove that : (Cosecθ - cotθ)^2 = 1-cosθ/1+cosθ ...|| Class 10 || NCERT Maths & rd question ||
Trigonometry Ex :- 8.5 Question no. 5. (i). (Cosecθ - Cotθ)² = (1 - Cosθ)/(1 + Cosθ). Trigonometry Ex :- 8.5 Question no. 5. (i). (Cosecθ - Cotθ)² = (1 - Cosθ)/(1 + Cosθ).
Q54 | Prove that (cosec⁡θ - cot⁡θ)^2 = (1 - cos⁡θ)/(1 + cos⁡θ) | cosec theta - cot theta whole squar Q54 | Prove that (cosec⁡θ - cot⁡θ)^2 = (1 - cos⁡θ)/(1 + cos⁡θ) | cosec theta - cot theta whole squar
(Cosec Theta-Cot Theta)2=1-Cos Theta/1+Cos Theta | (Cosec-Cot)2=1-Cos/1+Cos (Cosec Theta-Cot Theta)2=1-Cos Theta/1+Cos Theta | (Cosec-Cot)2=1-Cos/1+Cos
(cosec θ – cot θ) 2 = (1-cosθ)/(1+cosθ) (cosec θ – cot θ) 2 = (1-cosθ)/(1+cosθ)
cosec theta - cot theta whole square = 1-cos theta/1+cos theta cosec theta - cot theta whole square = 1-cos theta/1+cos theta
prove that (cosec θ - cot θ)² = 1 - cos θ upon 1 + cos θ prove that (cosec θ - cot θ)² = 1 - cos θ upon 1 + cos θ
If cosecθ+cotθ = p then prove that cosθ = p^2 - 1/p^2 + 1 . If cosecθ+cotθ = p then prove that cosθ = p^2 - 1/p^2 + 1 .