Show that the middle term in the expansion of `(1+x)^(2n)` is `(1. 3. 5.dotdot(2n-1))/(n !)` `2n...

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The middle term in the expansion of (1+x)^2 n is (1) (2 n) !/n ! x^2 (2) (2 n) !/n !(n-1) ! x^n+1... The middle term in the expansion of (1+x)^2 n is (1) (2 n) !/n ! x^2 (2) (2 n) !/n !(n-1) ! x^n+1...
If the middle term in the expansion of (x^2+1/x)^n is 924 x^6, then n= (1) 10 (2) 12 (3) 14 If the middle term in the expansion of (x^2+1/x)^n is 924 x^6, then n= (1) 10 (2) 12 (3) 14
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