In ∆ ABC AD perpendicular to BC and AD2=BD×CD. Prove that AB2+AC2=(BD+CD)2​#shorts #sslcexam2023

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In triangle ABC, AD is perpendicular to BC such that AC^2 = BD.CD . Prove that triangle ABC is In triangle ABC, AD is perpendicular to BC such that AC^2 = BD.CD . Prove that triangle ABC is
In △ABC, if AD⊥BC and AD^2=BD×DC, prove that ∠BAC=90°. In △ABC, if AD⊥BC and AD^2=BD×DC, prove that ∠BAC=90°.
In triangle ABC DE||BC .if AD=5cm,BD=7cm ,AC=18cm find the length of AE#shorts #sslcexam2023 In triangle ABC DE||BC .if AD=5cm,BD=7cm ,AC=18cm find the length of AE#shorts #sslcexam2023
The perpendicular from A on side BC of a ABC intersects BC at D such that DB = 3 CD. Prove that ... The perpendicular from A on side BC of a ABC intersects BC at D such that DB = 3 CD. Prove that ...
In given Fig. ∠BAC=90° and segment AD⊥BC. Prove that AD^2=BD×DC. In given Fig. ∠BAC=90° and segment AD⊥BC. Prove that AD^2=BD×DC.
AD, BE and CF are medians of a ∆ ABC. Prove that : 3(AB^2 + BC^2 + AC^2 ) = 4(AD^2 + BE^2 + CF^2) AD, BE and CF are medians of a ∆ ABC. Prove that : 3(AB^2 + BC^2 + AC^2 ) = 4(AD^2 + BE^2 + CF^2)
In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD In figure ∠ACB=90 & CD⊥ AB, Prove that CD²=BD×AD
In the given figure, ∠ B A C=90^∘ and A D ⊥ B C. Then, (a) B C · C D=B C^2 (b) A B · A C=B C^2 (c... In the given figure, ∠ B A C=90^∘ and A D ⊥ B C. Then, (a) B C · C D=B C^2 (b) A B · A C=B C^2 (c...