log x +log y = log xy

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log xy = log x + log y proof log xy = log x + log y proof
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If logx+logy = 7xy then prove log ( (𝑥+𝑦)/3 )= 1/(2 ) ( log x + log y ) If logx+logy = 7xy then prove log ( (𝑥+𝑦)/3 )= 1/(2 ) ( log x + log y )