1.82 g of a metal requires 32.5 ml of 1 N HCI to dissolve it . What is the equivalen

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1.82 g of a metal required 32.5 mL of N-HCl to dissolve it what is the equivalent weight of metal? 1.82 g of a metal required 32.5 mL of N-HCl to dissolve it what is the equivalent weight of metal?
To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equivalent weight of metal? | 12... To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equivalent weight of metal? | 12...
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A quantity of 1  g of metal carbonate was dissolved in 25 ml of normal HCl. The resulting liquid ... A quantity of 1  g of metal carbonate was dissolved in 25 ml of normal HCl. The resulting liquid ...
Xg of metal(eq.wt=12) was completely dissolved in 100cc of N/2 HCL. The Volume was made upto 500cc. Xg of metal(eq.wt=12) was completely dissolved in 100cc of N/2 HCL. The Volume was made upto 500cc.
`1g` of the carbonate of a metal was dissolved in `25mL` of `N-HCl`. Te resulting liquid `5 mL` ... `1g` of the carbonate of a metal was dissolved in `25mL` of `N-HCl`. Te resulting liquid `5 mL` ...
Xg of a metal (equ. wt=12) was completely dissolved in 100cc of N/2 HCl solution . It is found that Xg of a metal (equ. wt=12) was completely dissolved in 100cc of N/2 HCl solution . It is found that
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