, 25  mL of 0.50 MH_2O_2 solution is added to 50  mL of 0.20 MKMnO_4 in acid solution. Which of t...

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`25 mL` of `0.50M H_(2)O_(2)` solution is added to `50 mL` of `0.20 M KMnO_(4)` `25 mL` of `0.50M H_(2)O_(2)` solution is added to `50 mL` of `0.20 M KMnO_(4)`
25 ml of 0.50M H2O2 solution is added to 50ml of 0.20M | Equivalence weight | Equivalance master 25 ml of 0.50M H2O2 solution is added to 50ml of 0.20M | Equivalence weight | Equivalance master
2 KMnO4 + H2O2 → 2 MnO2 + 2 O2 + 2 KOH 2 KMnO4 + H2O2 → 2 MnO2 + 2 O2 + 2 KOH
1g of a divalent metal was dissolved in 25ml of 2N H2So4(f=1.01). The excess acid required 25.1ml 1g of a divalent metal was dissolved in 25ml of 2N H2So4(f=1.01). The excess acid required 25.1ml
50  mL of 0.5 M oxalic acid is needed to neutralise 25  mL of sodium hydroxide solution. The amou... 50  mL of 0.5 M oxalic acid is needed to neutralise 25  mL of sodium hydroxide solution. The amou...
78. When 85.0 mL of 0.250 M Ba(OH)_2 solution is added to 85.00 mL of 0.250 M Al(NO_3)_3 solution, … 78. When 85.0 mL of 0.250 M Ba(OH)_2 solution is added to 85.00 mL of 0.250 M Al(NO_3)_3 solution, …
Redox Titrations | A level Chemistry | Question Walkthrough Redox Titrations | A level Chemistry | Question Walkthrough
Redox titrations iodine and thiosulphate example calculations from www.ChemistryTuition.Net Redox titrations iodine and thiosulphate example calculations from www.ChemistryTuition.Net