If tanθ+sinθ=m and tanθ-sinθ=n,then show that m^2-n^2=4√mn CLASS-10 TRIGONOMETRY IMPORTANT PROBLEM

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If tan theta + sin theta = m and tan theta - sin theta = n, show that m^2 - n^2= 4√mn. Trigonometry If tan theta + sin theta = m and tan theta - sin theta = n, show that m^2 - n^2= 4√mn. Trigonometry
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If tanΘ + sinΘ = m and tanΘ - sinΘ = n, then show that m² - n² = 4 √mn. If tanΘ + sinΘ = m and tanΘ - sinΘ = n, then show that m² - n² = 4 √mn.
if tanθ+sinθ=m, tanθ-sinθ=show that m^2-n^2=4√mn if tanθ+sinθ=m, tanθ-sinθ=show that m^2-n^2=4√mn
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If tanθ+sinθ=m, tanθ-sinθ=n Show that m^2 〖-n〗^2 = 4√mn If tanθ+sinθ=m, tanθ-sinθ=n Show that m^2 〖-n〗^2 = 4√mn
If tan theta + sin theta = m and tan theta - sin theta = n, show that m^2 - n^2 = 4√mn /Trigonometry If tan theta + sin theta = m and tan theta - sin theta = n, show that m^2 - n^2 = 4√mn /Trigonometry
"If `tantheta+sintheta=m` and `tantheta-sintheta=n ,` show that `m^2-n^2= 4sqrt(n m)`" "If `tantheta+sintheta=m` and `tantheta-sintheta=n ,` show that `m^2-n^2= 4sqrt(n m)`"