Number of Ordered Pairs (r, k) for which 6(35Cr) = (k² – 3).36Cr+1 where k is an integer | Binomial

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The number of ordered pairs (r, k) for which 6. 35Cr = (k^ – 3). 36Cr + 1, where k is an integer, is The number of ordered pairs (r, k) for which 6. 35Cr = (k^ – 3). 36Cr + 1, where k is an integer, is
The number of ordered pairs (r k) for which 6.35Cr =(k²-3).36C(r+1) where k is an integer. The number of ordered pairs (r k) for which 6.35Cr =(k²-3).36C(r+1) where k is an integer.
The number of ordered pairs (r,k) for which 6.(35Cr)=(k^2 -3).(36Cr+1), where k is an integer, is... The number of ordered pairs (r,k) for which 6.(35Cr)=(k^2 -3).(36Cr+1), where k is an integer, is...
The number of ordered pairs (r, k) for which 6 .^35C_r= (k^2-3) ·^36C_r+1, where k is an integer,... The number of ordered pairs (r, k) for which 6 .^35C_r= (k^2-3) ·^36C_r+1, where k is an integer,...
A8_The number of ordered pair (r,k) for which A8_The number of ordered pair (r,k) for which
The number of ordered pairs (r, k) for which 6.35C, = (k2 – 3). 36C, 41, where k is an integer, is: The number of ordered pairs (r, k) for which 6.35C, = (k2 – 3). 36C, 41, where k is an integer, is:
Binomial Theorem | If (36Cr+1)x(k^2-3) = 35Cr.6, then Number | JEE Main Advanced Video Solution Binomial Theorem | If (36Cr+1)x(k^2-3) = 35Cr.6, then Number | JEE Main Advanced Video Solution
Know The Trick to Find the total number of Ordered Pairs of a and b | Math Olympics Know The Trick to Find the total number of Ordered Pairs of a and b | Math Olympics