If a^2 + b^2 = 7ab, prove that, log⁡{(a+b)/3} = (1/2) ( log⁡ a + log ⁡b )

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If `a^2+b^2=7ab`, prove that `[log(1/3)(a+b)]=1/2(loga+logb)`. If `a^2+b^2=7ab`, prove that `[log(1/3)(a+b)]=1/2(loga+logb)`.
Tn 11th maths exercise 2.12 question 5/if a^2 +b^2=7ab show that log a+b/3=1/2(log a+logb) Tn 11th maths exercise 2.12 question 5/if a^2 +b^2=7ab show that log a+b/3=1/2(log a+logb)
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यदि loga+b/3=1/2(loga+logb) है तो सिद्ध किजिए कि a^2+b^2=7ab यदि loga+b/3=1/2(loga+logb) है तो सिद्ध किजिए कि a^2+b^2=7ab
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If \( a^{2}+b^{2}=7 a b \), prove that \( 2 \log (a-b)=\log 5+\log a+\log b \) If \( a^{2}+b^{2}=7 a b \), prove that \( 2 \log (a-b)=\log 5+\log a+\log b \)