If α is a root of the equation x² + x +1=0 and ∑(αⁿ + 1/αⁿ)² = 20, then n is equal to

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If α is a root of the equation x^2+x+1=0 and sum k=1 to n (alpha^k+1/(alpha^2))^2=20 then n= If α is a root of the equation x^2+x+1=0 and sum k=1 to n (alpha^k+1/(alpha^2))^2=20 then n=
If alpha beta are the roots of the equation x 2 x 1 0 and S n 2023 alpha.... If alpha beta are the roots of the equation x 2 x 1 0 and S n 2023 alpha....
IIT-JEE MAINS 2025 APRIL//If α is a root of the equation x2+x+1=0 and ∑_(k=1)^n▒〖〖(α^k+1/α^k )〗^2=20 IIT-JEE MAINS 2025 APRIL//If α is a root of the equation x2+x+1=0 and ∑_(k=1)^n▒〖〖(α^k+1/α^k )〗^2=20
Q) If 𝛼 is a root of the equation 𝑥^2+𝑥+1=0 and ∑129_(𝑘=1)^𝑛 (𝛼^𝑘+1/𝛼^𝑘 )^2=20, then 𝑛 is equal to Q) If 𝛼 is a root of the equation 𝑥^2+𝑥+1=0 and ∑129_(𝑘=1)^𝑛 (𝛼^𝑘+1/𝛼^𝑘 )^2=20, then 𝑛 is equal to
If 𝛼 and 𝛽 are the roots of the equation x2-x+1=0, then 𝛼2009 + β2009 = If 𝛼 and 𝛽 are the roots of the equation x2-x+1=0, then 𝛼2009 + β2009 =
Q) If 𝛼 is a root of the equation 𝑥^2+𝑥+1=0 and ∑129_(𝑘=1)^𝑛 (𝛼^𝑘+1/𝛼^𝑘 )^2=20, then 𝑛 is equal to Q) If 𝛼 is a root of the equation 𝑥^2+𝑥+1=0 and ∑129_(𝑘=1)^𝑛 (𝛼^𝑘+1/𝛼^𝑘 )^2=20, then 𝑛 is equal to
How to solve : If α, β are the roots of, 𝒙^𝟐−𝒙−𝟏=0,𝑺_𝒏=𝟐𝟎𝟐𝟑𝜶^𝒏+𝟐𝟎𝟐𝟒𝜷^n | JEE Main | Sum of Series How to solve : If α, β are the roots of, 𝒙^𝟐−𝒙−𝟏=0,𝑺_𝒏=𝟐𝟎𝟐𝟑𝜶^𝒏+𝟐𝟎𝟐𝟒𝜷^n | JEE Main | Sum of Series
if α, β are roots of the equation x² + x + 2 = 0 ; (α¹⁰ + β¹⁰ )/( α^-10 +β^-10 ) = ? if α, β are roots of the equation x² + x + 2 = 0 ; (α¹⁰ + β¹⁰ )/( α^-10 +β^-10 ) = ?