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![Two resistors R1 = (4 ± 0.8) Ω and R2 = (4 ± 0.4)Ω : Error Analysis [JEE (Main)- 01st Sept. 2021 ]](https://i.ytimg.com/vi/dpDFM1kd_pk/hqdefault.jpg?sqp=-oaymwEjCOADEI4CSFryq4qpAxUIARUAAAAAGAElAADIQj0AgKJDeAE=&rs=AOn4CLCZfsdejREfM7biKdOTkm3atPCVsw)
Two resistors R1 = (4 ± 0.8) Ω and R2 = (4 ± 0.4)Ω : Error Analysis [JEE (Main)- 01st Sept. 2021 ]
Two resistors R1 = (4 ± 0.8) Ω and R2 = (4 ± 0.4) Ω are connected in parallel...| Doubtify JEE
Two resistors R1=(4±0.8)Ω and R2(4±0.4)Ω are connected in parallel. The equivalent resistance of
Two resistors R1 = (4 ± 0.8) and R2 = (4 ± 0.4) are connected #jee #jeemains2025 #jeemains #iit
Two resistors R1 = (4 +_ 0.8) Om and R2 = (4 +_ 0.4 ) Om are connected in parallel . The equivalent.
Two resistors R1 = (4 ± 0.8) and R2 = (4 ± 0.4) are connected #jee #jeemains2025 #jeemains #iit
Two resistors R1= (4+0.8) ohm and R2= 4+0.4) ohm are connected in parallel... | jee mains physics
Two resistors R1 = (4 ± 0.8) Ω and R2 = (4 ± 0.4) Ω are conn parallel JEE MAINS 2021#jee #neet2022