Prove the following that-tan3θ + cot3θ = secθ cosecθ – 2 sinθ cosθ1+ tan2θ 1+ cot2θ | CBSE Class 10

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29. Prove the following that- tan3θ/1+tan^2θ + cot3θ/ 1+cot^2θ = secθ cosecθ – 2 sinθ cosθ 29. Prove the following that- tan3θ/1+tan^2θ + cot3θ/ 1+cot^2θ = secθ cosecθ – 2 sinθ cosθ
Prove the following that- tan3θ/ (1+ tan2θ) + cot3θ/(1+ cot2θ) = secθ cosecθ – 2 sinθ cosθ Prove the following that- tan3θ/ (1+ tan2θ) + cot3θ/(1+ cot2θ) = secθ cosecθ – 2 sinθ cosθ
Prove the following that : tan^3θ/1+tan^2θ + cot^3θ/1+cot^2θ = secθcosecθ-2sinθcosθ...|| Class 10 || Prove the following that : tan^3θ/1+tan^2θ + cot^3θ/1+cot^2θ = secθcosecθ-2sinθcosθ...|| Class 10 ||
Prove the following that: tan^3θ/(1+tan^2θ)+cot^3θ/(1+cot^2θ)= secθcosecθ -2sinθcosθ Prove the following that: tan^3θ/(1+tan^2θ)+cot^3θ/(1+cot^2θ)= secθcosecθ -2sinθcosθ
Prove that : (tan³ θ/1+tan² θ) + (cot³ θ/1+cot² θ) = sec θ cosec θ - 2 sin θ cos θ. Prove that : (tan³ θ/1+tan² θ) + (cot³ θ/1+cot² θ) = sec θ cosec θ - 2 sin θ cos θ.
Ncert Exemplar Trigonometry tan³θ /(1+tan²θ+ cot³θ/(1+cot²θ) =secθ.cosecθ- 2sinθ.cosθ Ncert Exemplar Trigonometry tan³θ /(1+tan²θ+ cot³θ/(1+cot²θ) =secθ.cosecθ- 2sinθ.cosθ
IF BACKBENCHER BECOME TEACHER 😎| MATH TRICKS | SIN,COS,TAN | IF BACKBENCHER BECOME TEACHER 😎| MATH TRICKS | SIN,COS,TAN |
Prove that the following: (tan^3 θ)/(1+tan^2 θ)+cot^3/(1+cot^2 θ)=secθ⁡cosecθ-2 sinθ⁡cosθ Prove that the following: (tan^3 θ)/(1+tan^2 θ)+cot^3/(1+cot^2 θ)=secθ⁡cosecθ-2 sinθ⁡cosθ