O is the centre of the circle and BCD is tangent to it at C | Prove that opposite sides of a

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In given figure, O is centre of circle and ∠BCD is tangent to it at C, prove that ∠BAC + ∠ACD = 90°. In given figure, O is centre of circle and ∠BCD is tangent to it at C, prove that ∠BAC + ∠ACD = 90°.
In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠BAC + In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠BAC +
O is the center of the circle and BCD is a tangent to it at C. Prove that BAC + ACD =90° O is the center of the circle and BCD is a tangent to it at C. Prove that BAC + ACD =90°
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In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠𝑩𝑨𝑪+∠𝑨 In the given figure, O is the centre of the circle and BCD is tangent to it at C. Prove that ∠𝑩𝑨𝑪+∠𝑨
Everything About Circle Theorems - In 3 minutes! Everything About Circle Theorems - In 3 minutes!