tan⁡(π/4+x/2) = sec x + tan x how to prove this problem

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Prove that tan(π/4 +x/2)= secx+tanx Prove that tan(π/4 +x/2)= secx+tanx
prove tan(pi/4+x/2)=secx+tanx prove tan(pi/4+x/2)=secx+tanx
Prove the following identities: tan (π/4 + x) + tan (π/4 - x) = 2 sec 2x Prove the following identities: tan (π/4 + x) + tan (π/4 - x) = 2 sec 2x
Prove that :- tan(π/4 + x/2) = secx + tanx Prove that :- tan(π/4 + x/2) = secx + tanx
If y= log tan [(π/4 ) + (x/2)] then prove that dy/dx - sec x =0 #cbse If y= log tan [(π/4 ) + (x/2)] then prove that dy/dx - sec x =0 #cbse
Q) If 𝑦=log[tan(𝜋/4+𝑥/2)], then 𝑑𝑦/𝑑𝑥#cbse2026 #maths #class12maths #class12maths #class12 Q) If 𝑦=log[tan(𝜋/4+𝑥/2)], then 𝑑𝑦/𝑑𝑥#cbse2026 #maths #class12maths #class12maths #class12
Q22 If 𝑦 = log tan ( 𝜋 /4 + 𝑥/ 2 ), then prove that 𝒅𝒚/ 𝒅𝒙 − 𝐬𝐞𝐜 𝒙 = 𝟎 Q22 If 𝑦 = log tan ( 𝜋 /4 + 𝑥/ 2 ), then prove that 𝒅𝒚/ 𝒅𝒙 − 𝐬𝐞𝐜 𝒙 = 𝟎
sec theta + tan theta = tan(pi/4+theta/2) | secx+tanx= tan(pi/4+x/2) sec theta + tan theta = tan(pi/4+theta/2) | secx+tanx= tan(pi/4+x/2)