In an arithmetic progression, if S40=1030 and S12=57, then S30-S10 is equal to:

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In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 – S10 is equal to: In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 – S10 is equal to:
Arithmetic progression S40 = 1030 and S12=57 then S30-S10|JEE Main|24 Jan Shift 2|2025|BinomT|11|PYQ Arithmetic progression S40 = 1030 and S12=57 then S30-S10|JEE Main|24 Jan Shift 2|2025|BinomT|11|PYQ
In an arithmetic progression, if S40=1030 and S12=57, then S30-S10 is equal to: In an arithmetic progression, if S40=1030 and S12=57, then S30-S10 is equal to:
In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 - S10 isequal to In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 - S10 isequal to
In an arithmetic progression, if S_(40 )=1030 and S_(12 )=57 , the S_(30 )-S_(10 ) is equal toA) 510 In an arithmetic progression, if S_(40 )=1030 and S_(12 )=57 , the S_(30 )-S_(10 ) is equal toA) 510
In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 – S10 is equal to :(1) 525 (2) 5 In an arithmetic progression, if S40 = 1030 and S12 = 57, then S30 – S10 is equal to :(1) 525 (2) 5
Arithmetic progression, find the. first term and common ratio. Arithmetic progression, find the. first term and common ratio.
Arithmetic Progression - Sum of First n Terms of an Arithmetic Progression Arithmetic Progression - Sum of First n Terms of an Arithmetic Progression