Prove that : `2a^2+2b^2+2c^2-2ab-2bc-2ac= [(a-b)^2+(b-c)^2+(c-a)^2]`

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Prove that : `2a^2+2b^2+2c^2-2ab-2bc-2ac= [(a-b)^2+(b-c)^2+(c-a)^2]` Prove that : `2a^2+2b^2+2c^2-2ab-2bc-2ac= [(a-b)^2+(b-c)^2+(c-a)^2]`
सिद्ध कीजिये कि 2a^(2) + 2b^(2) +2c^(2) - 2ab - 2bc - 2ca = (a-b)^(2) + (b-c)^(2) + (c-a)^(2) |... सिद्ध कीजिये कि 2a^(2) + 2b^(2) +2c^(2) - 2ab - 2bc - 2ca = (a-b)^(2) + (b-c)^(2) + (c-a)^(2) |...
"Prove that: `2a^2+2b^2+2c^2-2a b-2b c-2c a=(a-b)^2+(b-c)^2+(c-a)^2`" "Prove that: `2a^2+2b^2+2c^2-2a b-2b c-2c a=(a-b)^2+(b-c)^2+(c-a)^2`"
proof// (a-b)^2= a^2-2ab+b^2 // proof// (a-b)^2= a^2-2ab+b^2 //
Prove that: `2a^2+2b^2-2a b-2b c-2c a=[(a-b)^2+(b-c)^2+(c-a)^2]` Prove that: `2a^2+2b^2-2a b-2b c-2c a=[(a-b)^2+(b-c)^2+(c-a)^2]`
(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca
#Formula (a+b)²=a²+b²+2ab #solution #Formula (a+b)²=a²+b²+2ab #solution
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca prove that- solved (a+b+c)²=a²+b²+c²+2ab+2bc+2ca prove that- solved