theta equal 1 divided by under root 7 then cosec square theta minus sec square theta divided by c

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#trigonometric Ratios if tan theta is equal to 1 by root 7 then cosec square theta + sec square #trigonometric Ratios if tan theta is equal to 1 by root 7 then cosec square theta + sec square
If tan θ = 1/√7, then (cosec² θ - sec² θ)/(cosec² θ + sec² θ) = (a) 5/7(b) 3/7(c) 1/12(d) 3/4 If tan θ = 1/√7, then (cosec² θ - sec² θ)/(cosec² θ + sec² θ) = (a) 5/7(b) 3/7(c) 1/12(d) 3/4
If tan θ = 1/√7, show that (cosec^2 θ - sec^2 θ)/(cosec^2 θ + sec^2 θ) = 4/3 | Trigonometry If tan θ = 1/√7, show that (cosec^2 θ - sec^2 θ)/(cosec^2 θ + sec^2 θ) = 4/3 | Trigonometry
Q29 | If tan⁡θ=1/√7 then show that (cosec^2⁡θ-sec^2⁡θ)/(cosec^2⁡θ+sec^2⁡θ)=3/4 | if tan theta=root 7 Q29 | If tan⁡θ=1/√7 then show that (cosec^2⁡θ-sec^2⁡θ)/(cosec^2⁡θ+sec^2⁡θ)=3/4 | if tan theta=root 7
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If tan θ = 1/√7, show that (cosec² θ - sec² θ)/(cosec² θ + sec² θ) = 3/4 If tan θ = 1/√7, show that (cosec² θ - sec² θ)/(cosec² θ + sec² θ) = 3/4
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