if 𝐲=𝐬𝐒𝐧 inverse β‘πŸ”π± root(πŸβˆ’πŸ—π±^𝟐 ) find π’…π’š/𝒅𝒙 I class 12 @mathsculeas

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y = sin inverse(πŸ”π’™βˆ’πŸ’root(πŸβˆ’πŸ’π’™^𝟐)/πŸ“)Find π’…π’š/𝒅𝒙 I class 12 @mathsculeas y = sin inverse(πŸ”π’™βˆ’πŸ’root(πŸβˆ’πŸ’π’™^𝟐)/πŸ“)Find π’…π’š/𝒅𝒙 I class 12 @mathsculeas
y = Sin Inverse (6x under root (1- 9x square), dy/dx = ?. Differential I Class12 Calculus I Previous y = Sin Inverse (6x under root (1- 9x square), dy/dx = ?. Differential I Class12 Calculus I Previous
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𝐲=sin inverse(𝟐^(𝒙+𝟏).πŸ‘^𝒙)/(𝟏+πŸ‘πŸ”^𝒙) find π’…π’š/𝒅𝒙 I class 12 @mathsculeas 𝐲=sin inverse(𝟐^(𝒙+𝟏).πŸ‘^𝒙)/(𝟏+πŸ‘πŸ”^𝒙) find π’…π’š/𝒅𝒙 I class 12 @mathsculeas
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