Let A={4^n-3n-1|n∈N} and B={9(n-1)|n∈N} where N is set of natural numbers. Prove that A⊂B

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If `A={4^(n)-3n-1:n in N) and B={9(n-1):n in N}` then If `A={4^(n)-3n-1:n in N) and B={9(n-1):n in N}` then
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