Let A=[■(α&-1@6&β)],α 0, such that det⁡〖(A)=0〗 and α+β=1. If I denotes 2 × 2 identity matrix, then

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Let A = [(α&-1@6&β)],α0, such that det(A) = 0 and α+β = 1. If I denotes 2×2 identity matrix, the Let A = [(α&-1@6&β)],α0, such that det(A) = 0 and α+β = 1. If I denotes 2×2 identity matrix, the
IIT-JEE MAINS 2025 APRIL//det(A)=0 and α+β=1.If I denotes identity matrix then the matrix (1+A)^8 is IIT-JEE MAINS 2025 APRIL//det(A)=0 and α+β=1.If I denotes identity matrix then the matrix (1+A)^8 is
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